AST 1440 – Radiation (2026)
Table of Contents
- Syllabus
- Thu 10 Sep - Introduction
- Mon 14 Sep - Basics of Radiative Transfer; the Eddington luminosity.
- Thu 17 Sep - Thermal Emission
- Mon 21 Sep - Absorption and emission lines
- Thu 24 Sep - Scattering
- Mon 28 Sep - EM waves, dispersion
- Thu 1 Oct - Polarization, generalized Faraday rotation
- Mon 5 Oct - Refraction, pulsar scintillation
- Thu 8 Oct - Retarded potentials, Cherenkov radiation
Syllabus
- Lectures
- AB 113, Monday 2 PM and Thursday 1 PM (with an hour before set aside for reading and problem solving)
- Lecturer
- Marten van Kerkwijk, MP 1203B, 416-946-7288, mhvk@astro.utoronto.ca
- Office hours
- Drop by my office, or by appointment
- Web page
-
http://www.astro.utoronto.ca/~mhvk/AST1440/
Almost all we know in astronomy comes from measurements of light. This course aims to help you gain the knowledge needed to understand these measurements, by learning at a basic level (i) the way light and matter interact, as governed by classical electrodynamics, relativity, and quantum mechanics; (ii) the resulting physical processes responsible for emission, absorption, transfer, and diffusion of radiation; and (iii) the astrophysically most relevant specific radiation processes and applications.
In this course, most lectures will have reading assignments, and you are expected to do these: while there will be time to answer questions about the readings, no lecture time will be spent regurgitating them. Instead, the lectures will be used for discussing (textbook) problems and relevant astronomical examples.
Note: AB 113 is reserved starting an hour prior to our meeting times, to enable getting together to read and discuss among yourselves.
List of topics
- Intensity, source function, black body, diffusion [RL 1]
- Wave-plasma interaction [RL 8]
- Accelerated charges, radiation reaction [RL 3]
- Free-free radiation and opacity [RL 5]
- Cyclotron and synchrotron radiation [RL 6]
- Compton and inverse Compton scattering [RL 7]
- Thermal distributions, Boltzman & Saha [RL 9]
- Atomic transitions; more complicated systems; collisions [RL 10,11]
- Applications! (of all of the above)
Course texts
The primary course text book is Radiative Processes in Astrophysics (RL) by Rybicki & Lightman, Wiley (online access via UofT library).
Two secondary book are Theoretical Astrophysics I: Astrophysical Processes (Pad) by Padmanabhan, Cambridge Univ. Press (online access via UofT library; more theoretical) and Astrophysical processes (Bradt) by Bradt, Cambridge Univ. Press (online access via UofT library; more applied).
A great resource, which includes links to mini-lectures by Aaron Parsons (UCB), is astrobaki:Radiative_Processes_in_Astrophysics.
Evaluation
- Three problem sets (30% total), due two weeks after posting:
set 1 (due Oct
1215) - Long presentation (20%) on a more advanced topic. Can be on any topic (with approval, but ideally directly relevant to your own research).
- Final exam (40%; oral).
Thu 10 Sep - Introduction
- Textbook
- No assigned reading, links I used included below.
- Animation shown in class
- https://github.com/mhvk/ast1440/blob/main/examples/accelerating_charge.py
Often useful to treat light we receive as a beam, not worrying that it is made of many photons (large N), though treating it as a wave when necessary. This is a macroscopic view.
In detail, we do need to know: how to decode the information the photons give, or indeed, how to even detect them. Hence, we need the microscopic view too.
Macroscopic view (brief summary of RL 1.1-1.4)
Define the specific intensity of a beam; then all bulk properties can be derived from it: flux \(F\), radiation density \(U\), radiation pressure \(P\), etc.
Basic picture is a beam of many photons going through sequence of layers, where the beam can interact with the matter, and energy can also be added to it. Ignoring scattering for now, one has \[ \frac{dI_{\rm \nu}}{ds} = -\alpha_{\rm \nu}I_{\rm \nu} + j_{\rm \nu} \] Often divide by the absorption coefficient \(\alpha_{\rm \nu}\), and define optical depth \(d\tau_{\rm \nu} = \alpha_{\rm \nu}ds\) and source function \(S_{\rm \nu} = j_{\rm \nu}/\alpha_{\rm \nu}\), \[ \frac{dI_{\rm \nu}}{d\tau_{\rm \nu}} = -I_{\rm \nu} + S_{\rm \nu} \]
Microscopic view (inspired by Pad 1.3, 1.4.2)
Basic ideas:
- Charges are accelerated by E, B (produced by other charges or otherwise);
- Acceleration produces EM waves, i.e., photons and thus E, B to interact with.
Classically, total power emitted (with acceleration determined in particle frame) is \[ \frac23 \frac{q^{\rm 2}a^{\rm 2}}{c^{\rm 3}}\qquad\hbox{(cgs, $\times1/4\pi\epsilon_{\rm 0}$ for SI)} \] Often, one can get surprisingly far with the classical picture, especially if taking into account special relativity. But in detail need quantum mechanics (often captured by correction factors).
Note: In class, I stated without much explanation that for a charge moving at constant velocity, the E field always points to the instantaneous position of the charge, even though it can only know about where the charge was at the retarded time. This comes about because the field depends on both the scalar potential of the charge and the vector potential due to the current corresponding to the charge's motion (which also leads to a magnetic field; you can play with this by inspecting \(B\) after running the animation code linked above). See RL 3.1-3.2, as well as the topical video at astrobaki:Larmor_Formula.
Example of estimates:
- Electron passing ion: Bremsstrahlung
Assume stationary proton and electron approaching with velocity \(v\) and impact parameter \(b\), then, \[ a\simeq\frac{e^{\rm 2}}{m_{\rm e}b^{\rm 2}} \] The timescale of the interaction will be \(t\simeq{}b/v\), so during the interaction the power emitted is, \[ {\cal E} \simeq \frac{e^{\rm 2}a^{\rm 2}}{c^{\rm 3}}\frac{b}{v} \simeq \frac{e^{\rm 6}}{c^{\rm 3} m_{\rm e}^{\rm 2} b^{\rm 3} v} \] Now for a set of electrons, one will have a typical \(b=n_{\rm ion}^{-1/3}\) and typical velocity \(v=(kT/m_{\rm e})^{1/2}\), so just from this estimate one sees that the total power will scale as \(n^{\rm 2}T^{-1/2}\).
- Electron in atom: transition rates between atomic states
Again assuming an electron and a proton (i.e., Hydrogen), it is bound, one must have electrostatic force balance the centrifugal one, i.e., \[ a \simeq \frac{e^{\rm 2}}{m_{\rm e}r^{\rm 2}} = \omega^{\rm 2}r, \] so the power \[ P \simeq \frac{e^{\rm 2}\omega^{\rm 4}r^{\rm 2}}{c^3}. \] Classically, this would decay, but in quantum mechanics there is a ground state. Assuming power emitted from an excited state still scales similarly, can estimate the lifetime. Equivalently, the decay rate should be, \[ Q = \frac{P}{E_{\rm line}}\simeq\frac{e^{\rm 2}\omega^{\rm 3}a_{\rm 0}^{\rm 2}}{\hbar c^{\rm 3}} \simeq \frac{e^{\rm 2}E_{\rm line}^{\rm 3}a_{\rm 0}^{\rm 2}}{\hbar^{\rm 4}c^{\rm 3}} \simeq \frac{e^{\rm 8}}{8c^{\rm 3}\hbar^{\rm 4}a_{\rm 0}} \simeq 2\times10^{\rm 9}{\rm\,s^{-1}} \] where we used \(r\simeq{}a_{\rm 0}\), \(E_{\rm line}=\hbar\omega\) and set \(E_{\rm line}\simeq{}e^{\rm 2}/2a_{\rm 0}\).
- Electron in B: cyclotron, and its relativistic version, synchrotron
In a B field, an electron will gyrate with a frequency \[ \omega_{\rm cyc}=\frac{qB}{m_{\rm e}c}, \] which will produce an oscillating wave, and one can calculate the power as before.
More interesting is to consider relativity. Without it, the emitted electric field is sinusoidal, so one gets emission just at \(\omega_{\rm cyc}\). With relativity and beaming, the shape distorts and harmonics appear. For highly relativistic electrons, it becomes more like a set of delta functions, which fourier transform to a smooth spectrum.
Mon 14 Sep - Basics of Radiative Transfer; the Eddington luminosity.
- Textbook
- RL 1.1-1.4 (and/or astrobaki:Specific_Intensity, astrobaki:Radiative_Transfer_Equation, astrobaki:Optical_Depth).
- Problems
- RL 1.1, 1.2,
1.3, 1.4. Do 1.4 first, with a short extension to it: the ULX (Ultra-Luminous X-ray source) M82 X-1 was observed to have an X-ray flux fX=4×10-12 erg cm-2 s-1. Estimate its luminosity, given that M82 is at d≈3.6 Mpc. What could you say about its mass?
Related to problem 1.4, we discussed where the assumptions underlying the Eddington luminosity might fail. For that purpose, we derived the electron scattering cross-section, and considered qualitatively how it can be reduced if the electron is bound or gyrating in a magnetic field.
RL Problem 1.4 - Eddington luminosity
From force balance, \[ f_{\rm grav}= g\rho = f_{\rm rad} = \frac{F}{c}\kappa\rho \qquad\Leftrightarrow \frac{GM\rho}{r^{\rm 2}} = \frac{\kappa{}\rho{}L}{4\pi{}r^{\rm 2}c}. \] For fully ionized material with fractional abundance \(X_{\rm H}\) of Hydrogen by mass, \[ L_{\rm edd} = \frac{4\pi{}GcM}{\kappa} = 4\pi{}GcM \frac{m_{\rm H}}{\sigma_{\rm T}\frac12(1+X_{\rm H})}. \]
Used through-out astronomy, for studies of accreting sources (X-ray binaries, AGN, etc.), to the superwind of AGB stars (though with opacity due to dust instead of electron-scattering).
For a source with given flux \(F\) at distance \(d\), it allows setting a mass constraint, \[ M \geq 4\pi{}d^{2 }F \frac{\sigma_{\rm T}\frac12(1+X_{\rm H})}{4\pi{}Gcm_{\rm H}}. \]
- Success: NS radius expansion bursts
X-ray bursts are caused by runaway fusion in a shell of accreted material. If \(L_{\rm edd}\) is reached, the shell expands, limiting fusion, leaving the source at \(L_{\rm edd}\). As fusion proceeds and the concentration of the fuel decreases, the shell contracts, i.e., the radius decreases, but the luminosity stays at at \(L_{\rm edd}\), so the effective temperature increases.
We discussed one of the two papers that described this first: Tamara et al., 1984PASJ...36..845T (the other is Lewin et al., 1984ApJ...277L..57L).
- Failure: Ultra-luminous X-ray sources
In the 1980s and 90s, X-ray sources were discovered in other galaxies that clearly has luminosities well over \(L_{\rm edd}\) for a neutron star, with implied minimum masses of \(\sim100M_{\rm \odot}\), surprisingly larger than Galactic stellar mass black holes (this is pre-LIGO!).
Everything was thrown off, though, by the discovery of pulsations by Bachetti et al. 2014Natur.514..202B, which immediately proved that the compact objects were neutron stars.
So, what went wrong? What assumptions broke down in the use of \(L_{\rm edd}\)?
- The derivation assumes irradiated gas is optically thin. This assumption breaks down inside stars, where the luminosity can be super-Eddington locally. But here we observe the X rays, so it cannot be too bad.
- First 4π in the mass limit is from \(L=4\pi{}d^{\rm 2}F\), which assumes the source emits isotropically. This is wrong in some cases (e.g.,, very badly so for gamma-ray bursts, GRBs). Here, though, the pulsations are not narrow, suggesting it is not a major problem.
- Second 4π comes from taking the flux local to a parcel of gas to be \(F=L/4\pi{}r^{\rm 2}\). That may be more relevant here: gas accreting on a magnetized neutron star gets channeled towards the magnetic poles and could emit sideways, out of the way of the infalling matter (which would thus see a flux less than \(L/4\pi{}r^{\rm 2}\)).
- We assumed standard electron scattering provides the smallest possible cross section. For strong magnetic fields, the cross-section is reduced (see below). This may matter here too.
- Success, indirectly: Magnetars
The pulsations discovered by Cline et al. 1980ApJ...237L...1C in the tail of the largest outburst of a soft gamma-ray repeater (SGR) localized to a supernova remnnant in the large Magellanic cloud (and thus with estimates of age and distance), proved that they could radiate orders of magnitude above \(L_{\rm edd}\). This provided perhaps the clearest evidence for them hosting very strong magnetic fields; see Paczynski 1992AcA....42..145P, together with rapid spin-down inferred from young age plus slow spin, and the magnetic field being the only plausible energy source - and that they thus are ``magnatars'' (Thomson & Duncan 1995MNRAS.275..255T).
Electron scattering: standard derivation and other cases.
I followed Pad §1.4.4 in my derivation of \(\sigma_{\rm T}\) and Pad §6.4 for the extension to Rayleigh scattering (or scattering by an electron in a strong field). RL §3.4 and §3.6 (latter starting at p.99) are similar.
Thu 17 Sep - Thermal Emission
- Textbook
- RL 1.5 (derivations do not have to be read in detail; see also astrobaki:Black-Body_Radiation, astrobaki:Local_Thermodynamic_Equilibrium, and, if you need a refresher, astrobaki:Boltzmann_distribution).
- Problems
- RL 1.3, 1.5, 1.6 (1.3 repeated from Monday so we can discuss it; 1.6 least important, more for information).
We discussed extensions to 1.3 and 1.5, on how to calculate S/N ratios for resolved and unresolved sources in the presence of background light, as well as on how brightness temperature is used in radio astronomy. We did not end up discussing 1.6, but some notes are added about it regardless.
RL problem 1.3 - Implications for S/N ratios
Consider an observation of an X-ray emitting cloud with radius \(R\) at distance \(d\), observed with a detector with acceptance opening half-angle \(\Delta\theta\) (and thus \(\Delta\Omega_{\rm det}=\pi\Delta\theta^{\rm 2}\)), effective detector area \(A_{\rm eff}\) (geometric area times detection efficiency), integration time \(\Delta{}t\) and bandwidth \(\Delta\nu\).
Unlike in the problem in the textbook, let's for simplicity assume that the cloud is optically thick, so \(I=C\) for \(\theta\leq{}R/d\) and 0 otherwise. We also define \(\Delta\Omega_{\rm src}=\pi(R/d)^{\rm 2}\).
- Source dominates.
From the source, the number of photons we get is \[ N_{\rm src} = I_{\rm src}\min(\Delta\Omega_{\rm det}, \Delta\Omega_{\rm src})A_{\rm eff}\Delta{}t\Delta\nu. \] If there is no background (or the source dominates over it), the signal-to-noise is simply \(N_{\rm src}^{1/2}\) and the maximum signal-to-noise ratio is obtained when the source is completely inside the angular acceptance region, i.e., when \(\Delta\Omega_{\rm det}\geq\Delta\Omega_{\rm src}\).
- Background dominates
If there is a background with constant intensity, then that causes an additional number of photons, \[ N_{\rm bkg} = I_{\rm bkg}\Delta\Omega_{\rm det}A_{\rm eff}\Delta{}t\Delta\nu. \] The S/N ratio is then \(N_{\rm src}/(N_{\rm src}+N_{\rm bkg})^{1/2}\). For the background limited case, as long as the source is resolved, \(S/N\propto\Delta\Omega_{\rm det}^{1/2}\), while if it is unresolved, \(S/N\propto\Delta\Omega_{\rm det}^{-1/2}\), so the optimal aperture just encloses the source (for the case where \(I(\theta)\) is not distributed as a top-hat, one would need to be more careful).
- Diffraction-limited telescope
A diffraction-limited telescope has \(\Delta\Omega_{\rm det}\simeq(\pi/4)(\lambda/D)^{\rm 2}\) (size of the wiki:Airy_Disk) and Aeff≅(π/4)D2, so in the background limited case, optimal \(S/N\propto(A_{\rm eff}/\Delta\Omega_{\rm det})^{1/2}\propto{}D^{\rm 2}\). The time needed to integrate to a given depth thus scales as \(D^{-4}\).
On the ground, the angular scale is limited by seeing (see wiki:Astronomical_seeing) instead of diffraction, so \(S/N\propto{}D/\theta_{\rm seeing}\). A good observing site really helps, as does adaptive optics.
RL problem 1.5 - Brightness temperature
The brightness temperature is often used in radio astronomy. In the problem set, one first calculates \(I_{\rm \nu}\) and then uses it to calculate \(T_{\rm b}\). Combining the two, \[ T_{\rm b} = \frac{f_{\rm \nu}}{\Delta\Omega}\frac{\lambda^{\rm 2}}{2k} \] In the problem, the source is resolved, but what if it is unresolved? Then, one can use that \(\Delta\Omega A=\lambda^{\rm 2}\) (plausible with \(\Delta\Omega\simeq(\pi/4)(1.22\lambda/D)^{\rm 2}\) and \(A=(\pi/4)D^{\rm 2}\), but exact; e.g., https://www.cv.nrao.edu/~sransom/web/Ch3.html). So, \[ T_{\rm b} = \frac{f_{\rm \nu}A^{}}{2k} = \frac{P_{\rm \nu}}{2k} \] where \(P_{\rm \nu}\) is the power received by the telescope. Often, the noise in a telescope system is characterized by an equivalent system temperature \(T_{\rm sys}=P_{\rm noise}/2k\).
For further radio telescope terminology, an effective area can be defined by \(A_{\rm eff}=P_{\rm \nu}/f_{\rm \nu}\), or, in terms of the brightness temperature, one has a forward gain \(G=A_{\rm eff}/2k=T_{\rm b}/f_{\rm \nu}\), typically given in units of [K/Jy]. More directly relevant for the sensitivity is the ratio \(G/T_{\rm sys}\). One can estimate this using measurements of the power on and off a source with known flux \(f_{\rm \nu}\), \(P'_{\rm on}\) and \(P'_{\rm off}\). Here, the primes indicate that these do not directly measure the power, but rather something proportional to it (due to amplification, digitization, etc.), i.e., \(P_{\rm off}=f_{\rm scl}2kT_{\rm sys}\) and \(P_{\rm on}-P_{\rm off}=f_{\rm scl}A_{\rm eff}f_{\rm \nu}\). But the scale factor drops out in ratios, so one can calculate \(G/T_{\rm sys}=(P_{\rm on}-P_{\rm off})/P_{\rm off}f_{\rm \nu}\). The inverse of this is known as the system equivalent flux density, \({\rm SEFD} = f_{\rm \nu}P_{\rm off}/(P_{\rm on}-P_{\rm off})\), the flux of a source for which the received power would equal that of the system noise.
RL problem 1.6 - Entropy of black body radiation
\(S=\frac43aVT^{\rm 3}\), so in an adiabatic process, \(T\propto1/R\), in contrast for an ideal gas for which \(T\propto{}V^{-(\gamma-1)}\propto1/R^{\rm 2}\). Hence, in an expanding universe, the radiation temperature scales as \(1/a=1+z\). It also means that supernovae would not be all that luminous if there was no reheating by radioactive decay: by the time the ejecta are large enough for photons to be able to diffuse out rapidly, they have cooled down a lot.
Mon 21 Sep - Absorption and emission lines
- Textbook
- RL 1.6
- Problems
- RL 1.8, 1.9 (and 1.7 if you have time). As an extension to 1.9, consider a case where the shell is replaced with a wind that moves outward radially. For a wind colder than the star, what line profile do you expect?
RL problem 1.7 - Einstein coefficients.
The problem discusses what happens in the absence of stimulated emission, or for neutrinos instead of photons. There is little to add to the solutions. But for the regular case, the most useful consequence arguably is just that it helps to understand why, if matter is roughly in Local Thermal Equilibrium (LTE), the source function \(S_{\rm \nu}=B_{\rm \nu}(T)\).
RL problem 1.8 - emission from a spherical cloud.
The easiest way to get the observed flux is to calculate the luminosity by adding up the optically thin emission, and then dividing by \(4\pi{}d^{\rm 2}\). But of course, the integral over specific intensity should give the same answer (and can be done correctly for all optical depths). One has, \[ F_{\rm \nu}=\int_{\rm \Omega} I_{\rm \nu} \cos \theta d\Omega = \int_{\rm 0}^{\rm \infty}I_{\rm \nu}(b)\frac{2\pi{}bdb}{d^{\rm 2}}, \] where we used cylindrical symmetry around the line of sight, and that \(\cos \theta\simeq1\) and \(d\Omega=2\pi{}bdb/d^{\rm 2}\) since the source is far away. With \(I_{\rm \nu}=2R(1-(b/R)^{\rm 2})^{1/2}j_{\rm \nu}\) and \(I_{\rm \nu}=B_{\rm \nu}\) for the optically thin and thick cases, respectively, this reproduces the solutions.
For the more general but thermal emission case, one would start with the solution to the radiative transfer equation along the line of sight to the observer (\(z\) axis, with object at origin and observer at \(z=+\infty\)), \[ I_\nu(b)=\int_{-\infty}^{\rm \infty} S_{\rm \nu}(b,z)(1- e^{-\tau_{\rm \nu}(b, z)} \] (this is just RL, Eq. 1.29, but without a \(I_{\rm \nu}^{\rm 0}\) term since we start at \(z=-\infty\)), where we can often use \(S_{\rm \nu}=B_{\rm \nu}(T)\). The optical depth is given by (RL, Eq. 1.26), \[ \tau_{\rm \nu}(b,z)=\int_{\rm z}^{+\infty} \alpha_{\rm \nu}(b, z') dz'. \]
RL problem 1.9 - A shell around a star, extension to stellar atmospheres
If one looks to a star through a shell transparent to the continuum but opague to a line, then in the line the flux will be lower if the shell is cooler than the star (absorption line) and higher if the shell is hotter (emission line). To the side of the star, one will always see an emission line, since there is no continuum.
For a star like the sun, the photosphere, where the continuum is formed, is surrounded by layers that are cooler, leading to the absorption spectrum seen in visible light. But further out, the temperature increases again, leading to the strongest lines to be in emission. See apod:230114 and apod:180409.
Seen at grazing incidence, one will reach \(\tau=1\) at a higher altitude than seen face on. Since the temperature at these higher laters is (generally) cooler, this leads to limb darkening. See apod:240513.
If the star has a wind, then generically absorption in the wind will be blue shifted, while emission will be over a large range of velocities. One gets a P Cygni profile. (If a star is accreting, e.g., because it is still forming, one can get a reversed P Cygni profile, where the absorption is on the redshifted end of the profile.)
Thu 24 Sep - Scattering
- Textbook
- RL 1.7, 1.8 (see also the nice video at astrobaki:Basic_Scattering, plus astrobaki:Random_Walks).
- Problems
- RL 1.10. This (fairly involved) problem is concerned with a semi-infinite, isothermal object. A general question is whether for such a set-up one expects deviations from a black-body spectrum. In particular, consider strong atomic transitions, for which absorption is often immediately followed by emission, effectively creating a scattering event. Thus, in such transitions, one has low \(\epsilon\equiv\alpha_{\rm \nu}/(\alpha_{\rm \nu}-\sigma_{\rm \nu})\). Given this, do you expect the spectrum to show line features? Can you think of way to explain that without the details of the radiative transfer equation?
RL problem 1.10 - influence of scattering
Discussed the implications of Eq.~7 in the RL solution (page 320), \(F_{\rm \nu}=(4\pi/\sqrt{3})B_{\rm \nu}[\sqrt\epsilon/(1+\sqrt\epsilon)]\), where \(\epsilon=\alpha_{\rm \nu}/(\alpha_{\rm \nu}+\sigma_{\rm \nu})\), in particular how even for the case that all properties (\(B_{\rm \nu}\), \(\alpha_{\rm \nu}\), and \(\sigma_{\rm \nu}\)) do not depend on depth inside the layer, one can get line features.
First, one sees that the more scattering dominates over absorption, the smaller \(\epsilon\) and thus the smaller the flux. I found it most useful to think about this as the large scattering opacity effectively slowing down the photons (since they have to random-walk towards the edge), thus reducing their rate and therefore the flux.
For resonant lines, photon absorption looks more like a scattering process, since after absorbing one photon, an ion will typically emit another one at the same frequency before it can be collisionally de-excited. Hence, \(\epsilon\) will be lower than in the continuum and thus such lines will appear as absorption lines (even though the temperature is constant throughout).
Conversely, for weak non-resonant lines, where de-excitation is dominated by collisions and the scattering thus dominated by continuum processes, \(\alpha_{\rm \nu}\) and thus \(\epsilon\) will be slightly larger than in the continuum and thus one expects (weak) emission features.
Emission lines from winds
I siscussed how to estimate line profiles both directly, as well as by calculating optical depths and using those to integrate the radiative transfer equation (assuming thermal emission). For both cases, the basic simplification we make is that natural and thermal line broadening will be substantially smaller than \(v_{\rm w}/c\).
Ignoring the contribution from the star or continuum, we first discussed how a line profile in the range \(\lambda_{\rm 0}(1\pm{}v_{\rm w}/c)\) arises, where we assume this is sampled at some (small) fixed wavelength spacing \(\Delta\lambda\).
For a given angle \(\theta\) relative to the direction to the observer, a constant velocity wind will have a radial velocity component \(v_{\rm rad}=-v_{\rm w}\cos \theta\), which will map to \(\lambda=\lambda_{\rm 0}(1+v_{\rm rad}/c)\). To get the range \(\Delta\theta\) corresponding to \(\Delta\lambda=\lambda_{\rm 0}\Delta{}v_{\rm rad}/c\), we use that \(dv_{\rm rad}/d\theta=v_{\rm w}\sin\theta\), so that \(\Delta\theta=\Delta{}v_{\rm rad}/(v_{\rm w}\sin \theta)=c(\Delta\lambda/\lambda_{\rm 0})/(v_{\rm w}\sin \theta)\propto1/\sin \theta\).
For optically thin emission, the total line luminosity at given frequency will be the emissivity \(j_{\rm \nu}\) times the volume \(V\). The volume for a given velocity \(v_{\rm rad}\) is a cone with opening angle \(\theta\) and width \(\Delta\theta\). For some range in radius \(\Delta{}R\), one thus has \(F_{\rm \nu}=\Delta{}R2\pi{}\sin \theta \Delta\theta/4\pi{}d^{\rm 2}\). Inserting the dependencies of \(\theta\) and \(\Delta\theta\), one has \(F_{\rm \nu}\propto\sin \theta / \sin \theta\), i.e., one expects a top-hat line profile, constant between \(-v_{\rm w}\) and \(+v_{\rm w}\).
For optically thick emission, at each velocity, the conical section is optically thick, so one observes flux from the area of that section, i.e., \(F_{\rm \nu}=\pi{}(\Delta{}R\sin \theta)^{\rm 2}B_{\rm \nu}/4\pi{}d^{\rm 2}\propto \sin^{\rm 2}\theta \propto 1-(v_{\rm rad}/v_{\rm w})^2\).
Of course, an actual integration of specific intensities should give the same result. We started by writing out the general expression for the flux, \[ F_{\rm \nu} = \int_{\rm \Omega} d\Omega\,I_{\rm \nu}(\Omega)\cos \theta = \int_{-\pi/2}^{\pi/2}d\theta\int_{\rm 0}^{\rm 2\pi}d\phi\sin \theta I_{\rm \nu}(\theta, \phi) \cos \theta. \] Definiting a cylindrical coordinate system centred on the star with the observer at \(z=d\) (\(d\) the distance), then for a line at given impact parameter (cylindrial radius) \(p\), with \(p/d\ll1\), one has \(\sin \theta\simeq{}p/d\), \(\cos \theta\simeq1\) and \(d\theta\simeq{}dp/d\). Assuming a spherical symmetric wind, i.e., no \(\phi\) dependence, \[ F_{\rm \nu} = \int_{\rm 0}^{\rm \infty} \frac{2\pi p dp}{d^{\rm 2}} I_{\rm \nu}(p). \] (Here, the integral is taken to \(\infty\), but it is assumed that \(I_{\rm \nu}(p)\rightarrow0\) while one still has \(p/d\ll1\).)
To see that this is tractible, I rederived RL Eq. 1.30 in class, which found that if the source function \(S_{\rm \nu}\) is constant, one has, \[ I_{\rm \nu} = S_{\rm \nu} (1 - e^{-\tau_{\rm \nu}^{\rm max}}) \] where the total optical depth, \[ \tau_{\rm \nu}^{\rm max} = \int_{-\infty}^{+\infty} dz\, \alpha_{\rm \nu}(r) = \int_{-\infty}^{+\infty} dz\,\alpha_{\rm o}(r) \phi(\nu-\nu_{\rm 0}(1-v_{\rm rad}/c)), \] where we used that for a line, \(\alpha_{\rm \nu} = \alpha_{\rm 0}\phi(\nu-\nu_{\rm 0})\), with \(\phi\) the profile function (defined such that \(\int_{\rm \nu}\phi(\nu-\nu_{\rm 0})d\nu=1\)). To make progress, one changes the integral to be over frequency, substituting \(\nu_0^{\rm \prime}=\nu_{\rm 0}(1-v_{\rm rad}/c)=\nu_{\rm 0}(1+(z/r)(v_{\rm w}/c))\). Hence, \(d\nu_{\rm 0}^{\rm \prime}/dz = (\nu_{\rm 0}v_{\rm w}/c)(1/r - z^{\rm 2}/r^{\rm 3}) = (\nu_{\rm 0}v_{\rm w}/c)(p^{\rm 2}/r^{\rm 3})\), and \(z=\pm\infty\) correspond to \(\nu_{\rm min,max}=\nu_{\rm 0}(1\pm{}v_{\rm w}/c)\), so that, \[ \tau_{\rm \nu}^{\rm max} = \int_{\nu_{\rm min}}^{\nu_{\rm max}} d\nu_{\rm 0}^{\rm \prime}\,\alpha_{\rm 0}(r) \phi(\nu-\nu_{\rm 0}^{\rm \prime}) \frac{c}{\nu_{\rm 0}v_{\rm w}}\frac{r^{\rm 3}}{p^{\rm 2}} = \alpha_{\rm 0}(r) \frac{c}{\nu_{\rm 0}v_{\rm w}}\frac{p}{\sin^{\rm 3}\theta}, \] where for the second equality we approximated the line profile as a delta function and used that \(r=p/\sin \theta\).
If we now take \(S_{\rm \nu}=B_{\rm \nu}\) and assume an isothermal wind so it is constant, and furthermore (more unrealistically) assume that the wind only emits between some \(R_{\rm low}\) and \(R_{\rm high}\), having \(\alpha_{\rm 0}\) constant within that range and zero outside, we can rederive the optically thin and thick cases. For optically thin, \[ F_{\rm \nu} \simeq \int_{p_{\rm low}}^{p_{\rm high}} \frac{2\pi p dp}{d^{\rm 2}} B_{\rm \nu}\alpha_{\rm 0}^{\rm \prime}\frac{p}{\sin^{\rm 3}\theta}, \] where \(p_{\rm low,high}=R_{\rm low,high}/\sin \theta\) and \(\alpha_{\rm 0}^{\rm \prime}=\alpha_{\rm 0}(c/\nu_{\rm 0}v_{\rm w})\) (which has units of inverse length). For given \(v_{\rm rad}\), \(\theta\) is constant, so the integral is simple, and one recovers that \(F_{\rm \nu}\) does not depend on \(\theta\), i.e., a top-hat line profile.
For an optically thick line, everything after \(B_{\rm \nu}\) disappears, so the integral again is simple and one recovers \(F_{\rm \nu}\propto\sin^{\rm 2}\theta\) as before.
Of course, these cases are not realistic, but they set the extremes, i.e., real line profiles should be intermediate. In particular, in general \(\alpha_{\rm 0}\) will not be constant; e.g., for lines driven by recombination, the opacity will scale as the product of the electron and ion densities, i.e., for a constant velocity wind one will have \(\alpha\propto{}n^{\rm 2}\propto1/r^{\rm 4}\). But it turns out this case is also tractable, as we will see in the problem set (which is partially inspired by the analytic calculations of profiles for Wolf-Rayet stars first done by Hillier et al. 1983ApJ...271..221H).
Mon 28 Sep - EM waves, dispersion
- Textbook
- RL 8.1 (with RL 2.1-2.3 for EM background; see also astrobaki:Plasma_Frequency, astrobaki:Electromagnetic_Plane_Waves).
- Problems
- RL 8.1, 2.2 (plus 8.2 if time).
RL problem 8.1 - conservation of Iν/nr2
Use that \(F_{\rm \nu}=\int_{\rm \Omega}I_{\rm \nu}\cos \theta d\Omega\) should be the same just above and below a plane separating a change in index of refraction. I found it easiest to consider is a source directly above the plane (i.e., \(\theta=0\) and \(\cos \theta=1\)), with opening \(\delta\theta\) and thus \(d\Omega=\pi(\delta\theta)^{\rm 2}\), and then apply Snell's law.
For a source at some arbitrary \(\theta\) not close to 0, \(\cos \theta d\Omega = \cos \theta d\theta\sin \theta d\phi\), and one finds the same result. This is easiest to see by realizing that the \(\cos \theta d\theta = d\sin \theta\) term and the \(\sin \theta\) both give a factor of \(n_{\rm r}^{\rm \prime}/n_{\rm r}\), while \(d\phi\) is the same on both sides.
RL problem 2.2 - in SI units
One advantage of SI units is that it makes it easier to keep track of where the ε and μ go. In class, I showed that for this problem, one finds \(m^2=\mu\epsilon(1+i\sigma/\epsilon\omega)\).
RL 8.1 - dispersion
In class, I followed the derivation of problem 2.2 with one for an electron in vacuum (microscopic prescripton), then identifying its effect with a different permeability \(\epsilon\). I noted that the derivation assumes an electron accelerated by the EM wave, but ignores its radiation, i.e., is incomplete in that sense. But for practical purposes, it does not matter too much; it just corresponds to a (very slight) reduction in intensity.
The final time delay due to dispersion is, \[ \Delta{}t(\nu) = \frac{e^{\rm 2}}{8\pi{}^{\rm 2}m_{\rm e}\epsilon_{\rm 0}c}\frac{DM}{\nu^{\rm 2}} = {\cal D}_{\rm 0}\frac{DM}{\nu^{\rm 2}} \] In pulsar timing, \({\cal D}_{\rm 0}\equiv(10^{\rm 4}/2.41){\rm s\,MHz^{\rm 2}\,cm^{\rm 3}/pc}\), with the value what one would find from the physical constants as known in the 1970s. This is not updated, since then DM values (dispersion measures, typically given in pc/cm3) could no longer be easily compared.
Generally, one should treat measured DM strictly as a fit of \(\Delta{}t(\nu)=D/\nu^{\rm 2}\), with an interpretation of \(D\) as a (scaled) electron column density. For instance, scattering may bias the measurements (it scales as \(1/\nu^{\rm 4}\), but may not be easily recognizable because of noisy measurements or a small bandwidth). See Kulkarni 2020arXiv200702886K.
Thu 1 Oct - Polarization, generalized Faraday rotation
- Textbook
- RL 2.4, 8.2 (see also astrobaki:Polarization, and astrobaki:Stokes_parameters and astrobaki:Faraday_rotation if needed).
- Problems
- RL 8.3.
Polarization
I mentioned the Poincaré sphere as a nice way to visualize polarization. See wiki:Unpolarized_light#Poincar%C3%A9_sphere.
Faraday rotation
We discussed how for weak magnetic fields, with observing frequency \(\nu\gg\nu_{\rm B}\), the two natural modes in the plasma are those of left and right cicrular polarization, which have different speeds, leading to regular Faraday rotation for linearly polarized waves.
But this changes when the magnetic field is very strong, or is nearly perfectly perpendicular to the direction of propagation. In that case, the two relevant modes are the O and X modes (with \(E\) parallel and perpendicular to the background \(B\), resp.). These differ in whether the electron can interact with the wave (by sliding along the field line) or cannot (since the electron would have to move perpendicular to B). Also in this case, waves that are not exactly O or X will be rotated around the relevant axis.
The relative importance of the two types is set by \(2(\nu/\nu_{\rm B})\cos(\alpha)\) (where \(\cos(\alpha)=\hat{k}\cdot\hat{B}\)). I showed examples from Li et al. 2019MNRAS.484.5723L (see, in particular, their Fig. 2), but the methods section of Li et al. 2023Natur.618..484L has more detail (and the paper itself presents a nice example in nature). See Pad §9.5 for detailed derivations.
Mon 5 Oct - Refraction, pulsar scintillation
- Textbook
- Revisit the part around Eq. 8.18 of RL.
- Problems
- Derive Eq. 8.18 (I went via the phase velocity, which describes how a wave front propagates, assumed a gradient in it, and related that to a gradient in index of refraction via \(v_{\rm ph}=c/n_{\rm r}\)).
Refraction
RL 8.1 briefly discusses refraction in a cold plasma, mentioning that the index of refraction \(n_{\rm r}=(1-(\nu_{\rm p}/\nu)^{\rm 2})^{1/2}\) (Eq. 8.16) and that light will get bend as \(dn_{\rm r}\hat{k}/dl=\nabla{}n_{\rm r}\) (Eq. 8.18). Integrating that over a not-too-large lens bending radiation by a small amount, one finds a bending angle \[ \alpha=\int_{\rm lens}\nabla n_{\rm r} dl = \frac{e^{\rm 2}}{8\pi^{\rm 2}m_{\rm e}\epsilon_{\rm 0}\nu^{\rm 2}}\nabla N_{\rm e} = \frac{r_{\rm e}}{2\pi}\lambda^{\rm 2}\nabla N_{\rm e}, \] where we used that \(r_{\rm e}=e^{\rm 2}/4\pi\epsilon_{\rm 0}m_{\rm e}c^{\rm 2}\). The constant terms are \(8314{\rm\,mas\,MHz^{\rm 2}cm^{\rm 2}cm}\) and \(0.0925{\rm\,mas\,m^{-2}cm^{\rm 2}cm}\), respectively.
We also briefly discussed applications to pulsar scintillation, and we found that typical values of \(\alpha\) around a few mas are required, which implies strangely large \(\nabla{}N_{\rm e}\simeq10^{\rm 3}{\rm\,cm^{-2}cm^{-1}}\). For the suggested physical picture of sheets seen at grazing incidence, see Pen & Levin 2014MNRAS.442.3338P, and for the paper showing the Toronto sky line, Liu et al. 2016MNRAS.458.1289L. For a more general overview of how scintillation works and how we can use it to learn about pulsars, see the background sections in the screens package documentation.
Thu 8 Oct - Retarded potentials, Cherenkov radiation
- Textbook
- RL 8.3, and RL 2.5, 3.1, and 3.2 for background (these back up some of the statements made in the first class).
- Problems
- No suitable problems in the book, so instead derive a few more properties of scintillation, using, like in class, the double pulsar as an example. Consider a screen consisting of many small lenses, each having column density gradients up to \(\nabla{}n_{\rm e}\simeq10^{\rm 3}{\rm\,cm^{-2}cm^{-1}}\). At \(\lambda=12{\rm\,cm}\), what is the corresponding maximum bending angle? Suppose this screen is halfway between us and the pulsar (\(d_{\rm psr}=700{\rm\,pc}\)), up to what separation from the line of sight (in au) will the lenslets be able to bend light in our direction? Given this, treating the lenslet array as an interstellar interferometer, what is its resolution (in μas)? And what spatial resolution at the pulsar does this correspond to? (I.e., how far can I move the pulsar and still see roughly the same interference pattern on Earth?) How does this compare with the projected semi-major axis of the binary orbit, \(x=1.415{\rm\,lt-s}\)? If I replaced the pulsar with a radio-emitting sun-like star, would I expect to see scintillation? How does the resolution at the pulsar scale with observing wavelength?